Integral distances

Find coordinates of a set of eight non-collinear planar points so that each has an integral distance from others.

(Proposed by Bhargav Gnv/FB/Math)

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These eight points all lie on a circle with radius 4225, so no three of them are collinear:

A = [1183, 4056]
B = [1183, -4056]
C = [2975, 3000]
D = [2975, -3000]
E = [-2975, 3000]
F = [-2975, -3000]
G = [-1183, 4056]
H = [-1183, -4056]

The 28 connecting segments all have integer length:

AB = 8112 , AC = 2080 , AD = 7280 , AE = 4290 , AF = 8190 , AG = 2366 ,
AH = 8450
BC = 7280 , BD = 2080 , BE = 8190 , BF = 4290 , BG = 8450 , BH = 2366
CD = 6000 , CE = 5950 , CF = 8450 , CG = 4290 , CH = 8190
DE = 8450 , DF = 5950 , DG = 8190 , DH = 4290
EF = 6000 , EG = 2080 , EH = 7280 , FG = 7280 , FH = 2080
GH = 8112