This is just a summing up! For details look at the previous post (below) with three Koch curve pictures.
If a ”snow flake” bounded by a Koch curve rotates around a horizontal axis through the centre the volume of the generated body is
For rotation around a vertical axis the volume becomes
VolV = 11πL³√3/243
VolH/VolV = 245√3/396 ≈ 1.07
L is the length of the side in the original equilateral tringle from which the Koch curve is generated. The horizontal axis has length 2L/3 and the vertical axis 2L/√3.